98m^2=18

Solution for 98m^2=18 equation:

98m^2=18

We move all terms to the left:

98m^2-(18)=0

a = 98; b = 0; c = -18;
Δ = b2-4ac
Δ = 02-4·98·(-18)
Δ = 7056
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{7056}=84$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-84}{2*98}=\frac{-84}{196}
=-3/7
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+84}{2*98}=\frac{84}{196}
=3/7
$